(2x-1)^2-3(2x-1)-4=0

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Solution for (2x-1)^2-3(2x-1)-4=0 equation: 



(2x-1)^2-3(2x-1)-4=0

We multiply parentheses

(2x-1)^2-6x+3-4=0

We add all the numbers together, and all the variables

-6x+(2x-1)^2-1=0

We move all terms containing x to the left, all other terms to the right

-6x+(2x-1)^2=1

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